SQL QUERIES - Part 2

51) Display the name of the employee who earns highest salary.

SQL>select ename from emp where sal=(select max(sal) from emp);

52) Display the employee number and name for employee working as clerk and earning highest salary among clerks.

SQL>select empno,ename from emp where where job='CLERK' and sal=(select max(sal) from emp where job='CLERK');

53) Display the names of salesman who earns a salary more than the highest salary of any clerk.

SQL>select ename,sal from emp where job='SALESMAN' and sal>(select max(sal) from emp where job='CLERK');

54) Display the names of clerks who earn a salary more than the lowest salary of any salesman.

SQL>select ename from emp where job='CLERK' and sal>(select min(sal) from emp where job='SALESMAN');

Display the names of employees who earn a salary more than that ofJones or that of salary grether than that of scott.

SQL>select ename,sal from emp where sal>(select sal from emp where ename='JONES')and sal> (select sal from emp where ename='SCOTT');

55) Display the names of the employees who earn highest salary in their respective departments.

SQL>select ename,sal,deptno from emp where sal in(select max(sal) from emp group by deptno);

56) Display the names of the employees who earn highest salaries in their respective job groups.

SQL>select ename,sal,job from emp where sal in(select max(sal) from emp

group by job);

57) Display the employee names who are working in accounting department.

SQL>select ename from emp where deptno=(select deptno from dept where dname='ACCOUNTING');

58) Display the employee names who are working in Chicago.

SQL>select ename from emp where deptno=(select deptno from dept where LOC='CHICAGO');

59) Display the Job groups having total salary greater than the maximum salary for managers.

SQL>SELECT JOB,SUM(SAL) FROM EMP GROUP BY JOB HAVING SUM(SAL)>(SELECT MAX(SAL) FROM EMP WHERE JOB='MANAGER');

60) Display the names of employees from department number 10 with salary greater than that of any employee working in other department.

SQL>select ename from emp where deptno=10 and sal>any(select sal from emp where deptno not in 10);

61) Display the names of the employees from department number 10 with salary greater than that of all employee working in other departments.

SQL>select ename from emp where deptno=10 and sal>all(select sal from emp where deptno not in 10);

62) Display the names of the employees in Uppercase.

SQL>select upper(ename)from emp;

63) Display the names of the employees in Lower case.

SQL>select lower(ename)from emp;

64) Display the names of the employees in Proper case.

SQL>select initcap(ename)from emp;

65) Display the length of Your name using appropriate function.

SQL>select length('name') from dual;

66) Display the length of all the employee names.

SQL>select length(ename) from emp;

67) select name of the employee concatenate with employee number.

SQL>select ename||empno from emp;

68) User appropriate function and extract 3 characters starting from 2 characters from the following string 'Oracle'. i.e the output should be 'ac'.

SQL>select substr('oracle',3,2) from dual;

69) Find the First occurance of character 'a' from the following string i.e 'Computer Maintenance Corporation'.

SQL>SELECT INSTR('Computer Maintenance Corporation','a',1) FROM DUAL;

70) Replace every occurance of alphabhet A with B in the string Allens(use translate function)

SQL>select translate('Allens','A','B') from dual;

71) Display the informaction from emp table.Where job manager is found it should be displayed as boos(Use replace function).

SQL>select replace(JOB,'MANAGER','BOSS') FROM EMP;

72) Display empno,ename,deptno from emp table.Instead of display department numbers display the related department name(Use decode function).

SQL>select empno,ename,decode(deptno,10,'ACCOUNTING',20,'RESEARCH',30,'SALES',40,'OPRATIONS') from emp;

73) Display your age in days.

SQL>select to_date(sysdate)-to_date('10-sep-77')from dual;

74) Display your age in months.

SQL>select months_between(sysdate,'10-sep-77') from dual;

75) Display the current date as 15th August Friday Nineteen Ninety Seven.

SQL>select to_char(sysdate,'ddth Month day year') from dual;

76) Display the following output for each row from emp table.scott has joined the company on Wednesday 13th August nineteen ninety.

SQL>select ENAME||' HAS JOINED THE COMPANY ON '||to_char(HIREDATE,'day ddth Month year') from EMP;

77) Find the date for nearest saturday after current date.

SQL>SELECT NEXT_DAY(SYSDATE,'SATURDAY')FROM DUAL;

78) Display current time.

SQL>select to_char(sysdate,'hh:MM:ss') from dual;

79) Display the date three months Before the current date.

SQL>select add_months(sysdate,3) from dual;

80) Display the common jobs from department number 10 and 20.

SQL>select job from emp where deptno=10 and job in(select job from emp

where deptno=20);

81) Display the jobs found in department 10 and 20 Eliminate duplicate jobs.

SQL>select distinct(job) from emp where deptno=10 or deptno=20

(or) 

SQL>select distinct(job) from emp where deptno in(10,20);

82) Display the jobs which are unique to department 10.

SQL>select distinct(job) from emp where deptno=10;

83) Display the details of those who do not have any person working under them.

SQL>select e.ename from emp,emp e where emp.mgr=e.empno group by e.ename having count(*)=1;

84) Display the details of those employees who are in sales department and grade is 3.

SQL>select * from emp where deptno=(select deptno from dept where dname='SALES')and sal between(select losal from salgrade where grade=3)and (select hisal from salgrade where grade=3);

85) Display those who are not managers and who are managers any one.

i)display the managers names

SQL>select distinct(m.ename) from emp e,emp m where m.empno=e.mgr;

ii)display the who are not managers

SQL>select ename from emp where ename not in(select distinct(m.ename) from emp e,emp m where m.empno=e.mgr);

86) Display those employee whose name contains not less than 4 characters.

SQL>select ename from emp where length(ename)>4;

87) Display those department whose name start with "S" while the location name ends with "K".

SQL>select dname from dept where dname like 'S%' and loc like '%K';

88) Display those employees whose manager name is JONES.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and e.ename='JONES';

89) Display those employees whose salary is more than 3000 after giving 20% increment.

SQL>select ename,sal from emp where (sal+sal*.2)>3000;

90) Display all employees while their dept names;

SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno;

91) Display ename who are working in sales dept.

SQL>select ename from emp where deptno=(select deptno from dept where dname='SALES');

92) Display employee name,deptname,salary and comm for those sal in between 2000 to 5000 while location is chicago.

SQL>select ename,dname,sal,comm from emp,dept where sal between 2000 and 5000 and loc='CHICAGO' and emp.deptno=dept.deptno;

93)Display those employees whose salary greter than his manager salary.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.sal>e.sal;

94) Display those employees who are working in the same dept where his manager is work.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.deptno=e.deptno;

95) Display those employees who are not working under any manager.

SQL>select ename from emp where mgr is null;

96) Display grade and employees name for the dept no 10 or 30 but grade is not 4 while joined the company before 31-dec-82.

SQL>select ename,grade from emp,salgrade where sal between losal and hisal and deptno in(10,30) and grade<>4 and hiredate<'31-DEC-82';

97) Update the salary of each employee by 10% increment who are not eligible for commission.

SQL>update emp set sal=sal+sal*10/100 where comm is null;

98) SELECT those employee who joined the company before 31-dec-82 while their dept location is newyork or Chicago.

SQL>SELECT EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPTWHERE (EMP.DEPTNO=DEPT.DEPTNO)AND HIREDATE <'31-DEC-82' AND DEPT.LOC IN('CHICAGO','NEW YORK');

99) DISPLAY EMPLOYEE NAME,JOB,DEPARTMENT,LOCATION FOR ALL WHO ARE WORKING AS MANAGER?

SQL>select ename,JOB,DNAME,LOCATION from emp,DEPT where mgr is not null;

100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS JONES? --[AND ALSO DISPLAY THEIR MANAGER NAME]?

SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR AND E.ENAME='JONES'; 

posted by Jeyakumar @ Friday, December 02, 2011,

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